X^2+10y-29=0

Solution for X^2+10y-29=0 equation:

X^2+10X-29=0

a = 1; b = 10; c = -29;
Δ = b2-4ac
Δ = 102-4·1·(-29)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6\sqrt{6}}{2*1}=\frac{-10-6\sqrt{6}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6\sqrt{6}}{2*1}=\frac{-10+6\sqrt{6}}{2}
$